In the equation:
\( 2H_2 + 1O_2 → 2H_2O \)
If you change \( 2H_2 \) to \( 3H_2 \) and balance the equation, the new equation becomes:
\( 3H_2 + 1.5O_2 → 3H_2O \)
To balance with whole numbers, you would actually use:
\( 4H_2 + 2O_2 → 4H_2O \)
Now, let's analyze the statements:
-
The equation will produce three molecules of water. - Incorrect. It produces four molecules of water after adjusting to balance.
-
Each oxygen molecule will combine with 2 hydrogen molecules with no leftover molecules. - Incorrect. With the balanced equation \( 4H_2 + 2O_2 → 4H_2O \), each \( O_2 \) combines with 4 hydrogen (2 molecules of \( O_2 \) combine with 8 hydrogen).
-
The result of the equation will be the same. - Incorrect. The amounts of reactants and products would differ after balancing.
-
It is not possible to produce water without leftover molecules. - Correct if referring to the original change (3H2 is not balanced). In the case of \( 3H_2 + 1.5O_2 → 3H_2O \), the original would require fractional amounts of \( O_2 \) or would indeed have leftover.
Thus, the correct statement in this context would be:
It is not possible to produce water without leftover molecules.