A wheel, starting from rest, has a constant angular acceleration of 1.8 rad/s2. In a 3.7-s interval, it turns through an angle of 52 rad. How long has the wheel been in motion at the start of this 3.7-s interval?
1 answer
The wheel has been in motion for 2.9 s at the start of the 3.7-s interval. This can be calculated using the equation for angular displacement: θ = ω0t + 1/2αt2, where θ is the angular displacement, ω0 is the initial angular velocity (which is 0 in this case), t is the time, and α is the angular acceleration. Rearranging the equation to solve for t gives t = 2θ/α. Plugging in the given values gives t = 2(52 rad)/(1.8 rad/s2) = 2.9 s.