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A wheel rotating with an angular velocity of 16rad/sec is slowed to an angular velocity of 4rad/sec by an angular acceleration of 2rad/sec^2.find

a. The angle turned in the process of slowing down
b. The time required

1 answer

a. V^2 = Vo^2 + 2a*d.
d = (V^2-Vo^2)/2a.
d = (16-256)/-4 = 60 Rad.

b. t = (V-Vo)/a = (4-16)/-2 = 6 s.