Asked by kelsey
A wheel on a game show is given an initial angular speed of 1.33 rad/s. It comes to rest after rotating through 3/4 of a turn.
(a) Find the average torque exerted on the wheel given that it is a disk of radius 0.76 m and mass 6.4 kg.
? N·m
sorry, I'm having converting issues...I don't see the link between theta, omega, moment of inirtia, torque...etc...
(a) Find the average torque exerted on the wheel given that it is a disk of radius 0.76 m and mass 6.4 kg.
? N·m
sorry, I'm having converting issues...I don't see the link between theta, omega, moment of inirtia, torque...etc...
Answers
Answered by
bobpursley
Torque=momentInertia*deacceleration
The average speed during deacceleration is 1.33/2, so the time to stop is displacement/avg velocity,or .75*2PI/(1.33/2)
deacceleration = wi/time
so you can find torque.
The average speed during deacceleration is 1.33/2, so the time to stop is displacement/avg velocity,or .75*2PI/(1.33/2)
deacceleration = wi/time
so you can find torque.
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