ma=P-T
Iε=M=TR
T=P-ma=P-mεR,
T=Iε/R.
P-mεR= Iε/R.
ε=PR/(I+mR²)=
=3.52•0.398/(0.0576+0.790•0.398²)=7.67 rad/s².
A wheel of radius 0.398 m is mounted on a frictionless horizontal axis. The rotational inertia of the wheel about the axis is 0.0576 kg·m2. A massless cord wrapped around the wheel is attached to a 0.790 kg block that slides on a horizontal frictionless surface. If a horizontal force of magnitude P = 3.52 N is applied to the block , what is the angular acceleration of the wheel? Take the clockwise direction to be the negative direction and assume the string does not slip on the wheel.
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