To find the total surface area of the cheese wheel, we can use the formula for the surface area of a cylinder, which is given by:
\[ \text{Surface Area} = 2\pi r(h + r) \]
where:
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.
From the question, we know:
-
The diameter of the cheese wheel is 6 inches, so the radius \( r \) is half of that: \[ r = \frac{6}{2} = 3 \text{ inches} \]
-
The height \( h \) of the cheese wheel is 2 inches.
Now we can plug in the values into the surface area formula:
\[ \text{Surface Area} = 2 \times 3.14 \times 3 \times (2 + 3) \]
Calculating the height plus radius: \[ h + r = 2 + 3 = 5 \]
Now plug that back into the surface area formula: \[ \text{Surface Area} = 2 \times 3.14 \times 3 \times 5 \]
Calculating step-by-step:
- Calculate \( 2 \times 3.14 = 6.28 \)
- Then \( 6.28 \times 3 = 18.84 \)
- Lastly, \( 18.84 \times 5 = 94.2 \)
Thus, the total surface area of the cheese wheel is:
\[ \text{Surface Area} = 94.2 \text{ square inches} \]
The correct response is: 94.2 square inches.