A weight of 15 N is located at a distance of 2.5 meters from the fulcrum of a simple lever. At what distance from the fulcrum should a weight of 20.0 N be placed on the opposite side of the fulcrum to balance the system?
4 answers
15 N * 2.5 m = 20.0 N * ?
1.875 so about 1.9m
15N is applied at a distance of 2.5m
how many cm away should 20 N be placed? you only show M
1 answer