To find the surface area of the cheese wedge, we need to calculate the area of each of the faces and then add them up.
1. The two triangular faces:
- The base of the triangle is the width of the prism which is 9 cm
- The height of the triangle is the height of the prism which is 5 cm
- The area of one triangle is (1/2) * base * height
- The total area of both triangles is 2 * (1/2) * 9 cm * 5 cm = 45 cm^2
2. The three rectangular faces:
- The area of each rectangle is length * height
- The total area of all three rectangles is 3 * 12 cm * 5 cm = 180 cm^2
Adding up the areas of all the faces, we get a total surface area of 225 cm^2.
Therefore, you would need 225 cm^2 of plastic wrap to cover the wedge of cheese.
A wedge of cheese is shaped like a triangular prism. How much plastic wrap is needed to cover the wedge of cheese?
The prism is 5 cm in height, 9 cm in width, and 12 cm in length.
5 answers
A wedge of cheese is shaped like a triangular prism. How much plastic wrap is needed to cover the wedge of cheese?
The area for a triangular prism is BH+(s1+s2+s3)L
S1/height= 5
S2/base= 12 cm
S3=13 cm
The prism is 9 cm in length
The area for a triangular prism is BH+(s1+s2+s3)L
S1/height= 5
S2/base= 12 cm
S3=13 cm
The prism is 9 cm in length
To calculate the total surface area of the cheese wedge, we can use the formula for the surface area of a triangular prism: A = BH + (s1 + s2 + s3)L.
Given:
- Base = 12 cm
- Height = 5 cm
- Slant height s1 = 5 cm
- Slant height s2 = 13 cm
- Length = 9 cm
Substitute these values into the formula:
A = 12 cm * 5 cm + (5 cm + 13 cm + 5 cm) * 9 cm
A = 60 cm^2 + 288 cm
A = 348 cm^2
Therefore, you would need 348 cm^2 of plastic wrap to cover the wedge of cheese.
Given:
- Base = 12 cm
- Height = 5 cm
- Slant height s1 = 5 cm
- Slant height s2 = 13 cm
- Length = 9 cm
Substitute these values into the formula:
A = 12 cm * 5 cm + (5 cm + 13 cm + 5 cm) * 9 cm
A = 60 cm^2 + 288 cm
A = 348 cm^2
Therefore, you would need 348 cm^2 of plastic wrap to cover the wedge of cheese.
NO THE DIMENSIONS ARE LITERALLY WHAT I SAID
S1 IS EQUAL TO 5
S2 IS EQUAL TO 12
S3 IS EQUAL TO 13
THE LENGTH IS 9 CM
S1 IS EQUAL TO 5
S2 IS EQUAL TO 12
S3 IS EQUAL TO 13
THE LENGTH IS 9 CM
Apologies for the oversight. Given the correct dimensions:
Base = s2 = 12 cm
Height = s1 = 5 cm
Slant height s3 = 13 cm
Length = 9 cm
Using the formula for the surface area of a triangular prism: A = BH + (s1 + s2 + s3)L
Substitute the values into the formula:
A = 12 cm * 5 cm + (5 cm + 12 cm + 13 cm) * 9 cm
A = 60 cm^2 + 270 cm
A = 330 cm^2
Therefore, you would need 330 cm^2 of plastic wrap to cover the wedge of cheese.
Base = s2 = 12 cm
Height = s1 = 5 cm
Slant height s3 = 13 cm
Length = 9 cm
Using the formula for the surface area of a triangular prism: A = BH + (s1 + s2 + s3)L
Substitute the values into the formula:
A = 12 cm * 5 cm + (5 cm + 12 cm + 13 cm) * 9 cm
A = 60 cm^2 + 270 cm
A = 330 cm^2
Therefore, you would need 330 cm^2 of plastic wrap to cover the wedge of cheese.