tan 37 = h/x
tan 58 = h/(5-x)
x tan 37 = (5-x) tan 58
x (tan 37+tan 58) = 5 tan 58
x = 5 tan 58/ (tan 58 + tan 37)
then
h = x tan 37
A weather balloon is sighted between points A and B which are 5 miles apart on level ground. The angle of elevation of the balloon from A is 37 degrees and it's angle of elevation from B is 58 degrees. Find the height, in feet, of the balloon above the ground.
2 answers
ok.... so what is the answer?