A weather balloon is inflated to a volume of 25.6L at a pressure of 736mmHg and a temperature of 31.9∘C. The balloon rises in the atmosphere to an altitude, where the pressure is 365mmHg and the temperature is -15.6∘C.
Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.
5 answers
The answer I got is 61.1 L but this is not correct. I do not understand what I am doing wrong.
Why didn't you show your work. Then we could find the trouble in an instant.
Use (P1V1/T1) = (P2V2/T2) and remember T must be in kelvin.
Use (P1V1/T1) = (P2V2/T2) and remember T must be in kelvin.
That is the equation that I used.
P1V1T2/T1P2 = (736mmHg x 25.6 L x 304.9 K)/(365mmHg x 257.4K) = 61.1 L
P1V1T2/T1P2 = (736mmHg x 25.6 L x 304.9 K)/(365mmHg x 257.4K) = 61.1 L
You forgot to change the units of P from mmHg to atm. To do this, just divide the mmHg value by 760 mmHg/atm.
I've tried it by changing mmHg to atm and I still get 61.1L
2 answers