A wave sent out from a source is reflected back to the surs in 1.0×10^-3 if the velocity of the wave is 3.0×10^8ms^-1 the distance of the reflection from the source.

Answer 1

T = 1.0*10^-3/2 = 0.5*10^-3 = 5*10^-4 s.
d = V * T = 3*10^8 * 5*10^-4 =

Answer 2

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