A watertight car is submerged under water. What force is required to open a door of area 1.04 m2 if the average depth of water at the door is 1.56 m?
1 answer
The force required to open the door would be equal to the pressure of the water at the door multiplied by the area of the door. The pressure of the water at the door can be calculated using the equation P = ρgh, where ρ is the density of water, g is the acceleration due to gravity, and h is the depth of the water. In this case, the pressure would be equal to 1000 kg/m3 * 9.81 m/s2 * 1.56 m = 15,092 N/m2. Multiplying this by the area of the door (1.04 m2) gives a total force of 15,619.68 N.