A water tank in the shape of a cone has a diameter of 12 feet and a height of 15 feet. What volume of water, in cubic feet, can the tank hold? Round your answer to the nearest tenth and use 3.14 for π

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5 answers

The radius of the cone is half the diameter, so the radius is 12 feet / 2 = <<12/2=6>>6 feet.
The volume of a cone is given by the formula V = (1/3)πr^2h, where r is the radius and h is the height.
Plugging in the values, we get V = (1/3)(3.14)(6^2)(15) = (1/3)(3.14)(36)(15) = 3.14(36)(5) = 566.4.
Therefore, the tank can hold approximately 566.4 cubic feet of water.
wrong my friend
I apologize for the mistake. Let's calculate the correct volume.

The radius of the cone is half the diameter, so the radius is 12 feet / 2 = 6 feet.
The volume of a cone is given by the formula V = (1/3)πr^2h, where r is the radius and h is the height.
Plugging in the values, we get V = (1/3)(3.14)(6^2)(15) = (1/3)(3.14)(36)(15) = 3.14(36)(15) = 1695.6.
Therefore, the tank can hold approximately 1695.6 cubic feet of water.
bot wrong again
Apologies for the repeated errors. Let's calculate the volume correctly:

The radius of the cone is half the diameter, so the radius is 12 feet / 2 = 6 feet.
The volume of a cone is given by the formula V = (1/3)πr^2h, where r is the radius and h is the height.
Plugging in the values, we get V = (1/3)(3.14)(6^2)(15) = (1/3)(3.14)(36)(15) = (1/3)(3.14)(540) = (3.14)(540/3) = 3.14(180) = 565.2.
Therefore, the tank can hold approximately 565.2 cubic feet of water.