The volume of the water tank is given by V = (1/3)πr^2h, where r is the radius and h is the height.
At the start of pouring water, the height of the water is 0 cm.
After two minutes, the volume of water poured into the tank is 9π x 2 = 18π cm3.
Therefore, the height of the water after two minutes is h = (18π/πr^2) = (18/r^2) cm.
The rate of change of height of water two minutes after the start of pouring water is:
Rate of change = (18/r^2) - 0 = 18/r^2 cm/min
Since the radius of the base is 5 cm, the rate of change of height of water two minutes after the start of pouring water is:
Rate of change = 18/5^2 = 7.2 cm/min
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9 pi cm3/min. calculate the rate of change of height of water two minutes after the start of pouring water.
3 answers
the bot is still wrong, see my answer to the same question below
impatient much?
Once is enough, thank you.
Repeated postings will not get faster or better responses.
Once is enough, thank you.
Repeated postings will not get faster or better responses.