a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9 pi cm3/min. calculate the rate of change of height of water two minutes after the start of pouring water.

3 answers

The volume of the water tank is given by V = (1/3)πr^2h, where r is the radius and h is the height.

At the start of pouring water, the height of the water is 0 cm.

After two minutes, the volume of water poured into the tank is 9π x 2 = 18π cm3.

Therefore, the height of the water after two minutes is h = (18π/πr^2) = (18/r^2) cm.

The rate of change of height of water two minutes after the start of pouring water is:

Rate of change = (18/r^2) - 0 = 18/r^2 cm/min

Since the radius of the base is 5 cm, the rate of change of height of water two minutes after the start of pouring water is:

Rate of change = 18/5^2 = 7.2 cm/min
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