The volume of the water tank is (1/3)πr2h = (1/3)π(5)2(10) = 250π cm3.
The rate of change of height of water two minutes after the start of pouring water is (18π cm3)/(2 min) = 9π cm3/min.
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9 pi cm 3/min. calculate the rate of change of height of water two minutes after the start of pouring water.
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a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9 pi cm 3/min. calculate the rate of change of height of water 2 minutes after the start of pouring water.
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9pi cm^3/min. calculate the rate of change of height of water 2 minutes after the start of pouring water.
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9pi cm3/min. calculate the rate of change of height of water two minutes after the start of pouring water.
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Once is enough, thank you.
Repeated postings will not get faster or better responses.