A water tank has the shape of an inverted right circular cone whose base radius is equal to half its height. Water is being pumped in at 2 cubic meters per second. How fast is the water rising when the water is 3 meters deep?

Answer 1

radius = (1/2)h
r = (1/2)h
r = h/2

V = (1/3)πr^2 h
= (1/3)π(h^2/4)h
= (1/12)πh^3
dV/dt = (1/4)πh^2 dh/dt

when h = 3, dV/dt = 2
2 = (1/4)π(9) dh/dt
dh/dt = 8/(9π) m/s

Check my calculations, I did not write them out first.