A water tank decreases by 10 gallons every 3 hrs every day what is the total change in the amount of water in the tank after 6 days?

-80 gallons
-480 gallons
80 gallons
480 gallons

1 answer

To find the total change in the amount of water in the tank after 6 days, we first need to determine how much water is lost each day.

  1. The tank loses 10 gallons every 3 hours.
  2. There are 24 hours in a day.

Now, to calculate how many 3-hour intervals there are in a day: \[ \text{Number of 3-hour intervals in a day} = \frac{24 \text{ hours}}{3 \text{ hours/interval}} = 8 \text{ intervals} \]

Next, we calculate the total loss of water in one day: \[ \text{Water loss per day} = 10 \text{ gallons} \times 8 \text{ intervals} = 80 \text{ gallons} \]

Now, over 6 days, the total change in the amount of water can be calculated: \[ \text{Total water loss in 6 days} = 80 \text{ gallons/day} \times 6 \text{ days} = 480 \text{ gallons} \]

Since the amount of water in the tank is decreasing, the total change in the amount of water in the tank is: \[ \text{Total change} = -480 \text{ gallons} \]

Thus, the total change in the amount of water in the tank after 6 days is \(-480\) gallons.

The answer is \(-480\) gallons.