A water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days?(1 point)

Responses

80 gallons
80 gallons

−480 gallons
negative 480 gallons

480 gallons
480 gallons

−80 gallons
negative 80 gallons

1 answer

To determine the total change in the amount of water in the tank after 6 days, we first need to calculate how much water decreases in a single day.

The tank decreases by 10 gallons every 3 hours. In a day (24 hours), we can calculate how many 3-hour periods are in a day:

\[ \frac{24 \text{ hours}}{3 \text{ hours}} = 8 \text{ periods} \]

Now, we can calculate the total decrease in gallons for one day:

\[ 10 \text{ gallons} \times 8 = 80 \text{ gallons} \]

Next, we calculate the total decrease over 6 days:

\[ 80 \text{ gallons/day} \times 6 \text{ days} = 480 \text{ gallons} \]

Since the water is decreasing, we express this as a negative change:

\[ \text{Total change} = -480 \text{ gallons} \]

Therefore, the answer is:

\(-480\) gallons.