A water tank decreases by 10 gallons every 3 hours every day what is the total change in the amount of water in the tank after 6 days a negative 80 gallons B 80 gallons c480 gallons d-480 gallons

1 answer

To calculate the total change in the amount of water in the tank after 6 days, let's start with the rate of decrease.

The tank decreases by 10 gallons every 3 hours. First, we need to determine how many hours are in 6 days:

\[ 6 \text{ days} \times 24 \text{ hours/day} = 144 \text{ hours} \]

Next, we find out how many 3-hour intervals fit in 144 hours:

\[ \frac{144 \text{ hours}}{3 \text{ hours/interval}} = 48 \text{ intervals} \]

Now, we multiply the number of intervals by the decrease per interval:

\[ 48 \text{ intervals} \times 10 \text{ gallons/interval} = 480 \text{ gallons} \]

Since the tank is decreasing in water, the total change is a negative amount. Therefore, the total change in the amount of water in the tank after 6 days is:

\[ -480 \text{ gallons} \]

So the correct answer is d) -480 gallons.