A water tank decreases by 10 gallons every 3 hours each day. What is the total change in the amount of water in the tank after 6 days?

Answer 1

To calculate the total change in the amount of water in the tank after 6 days, we first determine the amount of water the tank loses each day.

The tank decreases by 10 gallons every 3 hours. There are 24 hours in a day, so we can find out how many 3-hour periods there are in a day:

\[ \text{Number of 3-hour periods in a day} = \frac{24 \text{ hours}}{3 \text{ hours}} = 8 \]

Each of these 3-hour periods contributes to a decrease of 10 gallons. Therefore, the total decrease in gallons per day is:

\[ \text{Daily decrease} = 10 \text{ gallons/period} \times 8 \text{ periods} = 80 \text{ gallons} \]

Now, to find the total decrease over 6 days, we multiply the daily decrease by the number of days:

\[ \text{Total decrease over 6 days} = 80 \text{ gallons/day} \times 6 \text{ days} = 480 \text{ gallons} \]

Thus, the total change in the amount of water in the tank after 6 days is:

\[ \boxed{480} \text{ gallons} \]

Answer 2

wrong

Answer 3

Let's go through the calculations again step by step.

1. Daily Water Loss:

   • The tank loses 10 gallons every 3 hours.
   • There are 24 hours in a day, so we need to calculate how many 3-hour intervals fit into 24 hours: \[ \text{Number of 3-hour intervals in a day} = \frac{24 \text{ hours}}{3 \text{ hours}} = 8 \text{ intervals} \]
   • Therefore, the water lost per day is: \[ \text{Daily loss} = 10 \text{ gallons/interval} \times 8 \text{ intervals} = 80 \text{ gallons} \]

2. Total Water Loss Over 6 Days:

   • Now, we multiply the daily loss by the number of days (6): \[ \text{Total loss over 6 days} = 80 \text{ gallons/day} \times 6 \text{ days} = 480 \text{ gallons} \]

So the total change in the amount of water in the tank after 6 days is indeed:

\[ \boxed{480} \text{ gallons} \]

If you still believe this is incorrect, could you please clarify where the misunderstanding might be?