A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally.

Question

One person hits the water 5.00 m from the end of the slide in a time of 1.000 s after leaving the slide.

Ignoring friction and air resistance, find the height H in the drawing.

meters?
P.S. (i tried to use h=ut + 1/2at^2)

Answer 1

Time, t = 1 s.
Vertical velocity, u = 0
H = ut+ (1/2)gt²
=0*1 -(1/2)(9.8)*1²
=-4.9 m

Note: the distance 5 m is not used. When the initial velocity of 5 m/s does not hvae a vertical component, the initial velocity does not affect the outcome.

Answer 2

Well, your answer is partially right so it's wrong.
The right answer is:

H = h1 + h2 = [ut + (1/2)gt^2] + [(1/2)v^2/g] = (0*1 + (1/2)*9.81*1^2) + [(1/2)*(5.00m/1s)^2 / 9.81) = 6.17m