A water resrvoir in form of a cone is mounted on a hemispherical bowl.if the height of that one is six times its radius and the volume of the resevoir is 333 1/3 pi cm cubic,calculate correct to decimal place. a) the total surface area of the resevoir. b) curved surface area of the cone. c) volume of the reservoir
2 answers
Thank you
r=6h, so
v = π/3 r^2h = 12πh^3 = 1000/3 π, so h = 3 cm
the slant height s=√(h^2+r^2) = √(3^2+18^2) = 18.25
(a) πr(r+s)
(b) πrs
(c) you just said the volume was 333 1/3 π
But I don't see any mention of the hemisphere, which was apparently not part of the reservoir. Check for typos and make any fixes needed. And I know you have made some typos.
v = π/3 r^2h = 12πh^3 = 1000/3 π, so h = 3 cm
the slant height s=√(h^2+r^2) = √(3^2+18^2) = 18.25
(a) πr(r+s)
(b) πrs
(c) you just said the volume was 333 1/3 π
But I don't see any mention of the hemisphere, which was apparently not part of the reservoir. Check for typos and make any fixes needed. And I know you have made some typos.