A water balloon is thrown straight down at 10.0 m/s from a second floor window, 5.00 m above ground level.

1) How fast is the balloon moving when it hits the ground? (Express your answer to three significant figures.)

2 answers

h = -1/2 g t^2 - 10.0 t + 5.00

find the time (T) when h equals zero (impact)

v = 10.0 + g T
v^2 = vo^2 - 2g(y-yo)
v^2 = 10^2 - 2(9.8)(0-5)
v = √198
v = 14.1 m/s