Pythagorean Theorem
a^2 + b^2 = c^2
2^2 + 3^2 = c^2
4 + 9 = c^2
13 = c^2
3.61 = c
A walks 2Km south to B, she the walks 3km west to C. Find the distance and bearing from C and A
4 answers
This questions is like a word problem for a triangle. Draw point A and head 2 unit down draw point B there, then draw a point 3 units to the right. draw point C there it should be a right triangle with C-A as the hypotenuse. So distance C-A equals the square root of 2^2 + 3^2 using the pythagorean theorem hope this helps.
5KM 236 DEGREES
U are stupid