The reason you have a negative sign is because you dropped the sign on the -0.8. When that term is moved to the right it changes to a + value.
I don't know why you came up with 187. You didn't show your work so I can't find the error but I didn't end up with that number. Try punching in the numbers again.
A volume of 80.0mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If the final temperature of the system is 21.20 ∘C , what is the mass of the steel bar?
Use the following values:
specific heat of water = 4.18 J/(g⋅∘C)
specific heat of steel = 0.452 J/(g⋅∘C)
When I enter the formula I get -187.264 which is not correct.
My formula is x*.452*19.2+80*4.18*-.8
1 answer
1 answer