The balanced chemical equation for the reaction is:
2SO4(g) → 2SO3(g)
According to the equation, two moles of SO3 are formed from two moles of SO4. We know the volume (50 cm3) and the concentration (4) of the starting gas, so we can calculate the number of moles:
n = C x V/1000
n = 4 x 50/1000 = 0.2 moles
Since the stoichiometry of the reaction is 1:1, the number of moles of SO3 produced is also 0.2 moles. The volume of the new gas can be calculated using the ideal gas law:
PV = nRT
Assuming constant temperature and pressure, we have:
V = nRT/P
Using the values of n, R (the gas constant), T (the temperature), and P (the pressure), we can calculate the volume of the new gas:
V = 0.2 x 8.31 x 273/100000 = 0.0045 m3 or 4.5 L
The formula of the new oxide can be determined by dividing the number of moles of SO3 by the volume of the gas:
n(SO3)/V = 0.2/0.0045 = 44.4 mol/m3
The empirical formula of SO3 is SO3, so the molecular formula is also SO3. Therefore, the formula of the new oxide is SO3.
a volume of 50cm3 of sulphuric (4) oxide was passed over heated catalysts with new oxide of sulphur has been formed and none of the original gases remained.work out the formula of the new oxide
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1 answer