A volume of 40.0 of aqueous potassium hydroxide was titrated against a standard solution of sulfuric acid h2so4. What was the molarity of the solution if 20.02 of 1.50M h2s04 was needed?

Question

A volume of 40.0 of aqueous potassium hydroxide  was titrated against a standard solution of sulfuric acid h2so4. What was the molarity of the solution if 20.02 of 1.50M h2s04 was needed?

Who helps me to solve it for me.

DrBob222 · Answer

Technically the problem can't be solved because you have no units for 40.0 and 20.02. Assuming those are mL, the problem is solved as follows:

2KOH + H2SO4 ==> K2SO4 + 2H2O
mols H2SO4 = M x L = ?
mols KOH = 2x that (look at the equation coefficients)
Then M KOH = mols KOH/L KOH.