A voltage V across a resistance R generates a current I=VR. If a constant voltage of 4 volts is put across a resistance that is increasing at a rate of 0.3 ohms per second when the resistance is 4 ohms, at what rate is the current changing? (Give units.)
2 answers
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dR/dt = .3 ohms/s
I = 18V/R
d/dt(I) = d/dt(18V/R)
dI/dt(I) = dR/dt(18V/R)
dI/dt = dR/dt*(-18/R**2)
dI/dt = .3*(-18/4**2)
dI/dt = -.3375amp/s
Hope you understand my work! Cheerz
I = 18V/R
d/dt(I) = d/dt(18V/R)
dI/dt(I) = dR/dt(18V/R)
dI/dt = dR/dt*(-18/R**2)
dI/dt = .3*(-18/4**2)
dI/dt = -.3375amp/s
Hope you understand my work! Cheerz
3 answers