To find the correct corresponding \(y\)-values for the function \(h = -6t^2 + 33t + 6\) at the given \(x\)-values (\(t\)-values), we will calculate \(h\) for \(t = 0, 1, 2, 3, 4\).
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For \(t = 0\): \[ h(0) = -6(0)^2 + 33(0) + 6 = 6 \]
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For \(t = 1\): \[ h(1) = -6(1)^2 + 33(1) + 6 = -6 + 33 + 6 = 33 \]
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For \(t = 2\): \[ h(2) = -6(2)^2 + 33(2) + 6 = -6(4) + 66 + 6 = -24 + 66 + 6 = 48 \]
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For \(t = 3\): \[ h(3) = -6(3)^2 + 33(3) + 6 = -6(9) + 99 + 6 = -54 + 99 + 6 = 51 \]
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For \(t = 4\): \[ h(4) = -6(4)^2 + 33(4) + 6 = -6(16) + 132 + 6 = -96 + 132 + 6 = 42 \]
Now we have the corresponding \(y\)-values:
- \(h(0) = 6\)
- \(h(1) = 33\)
- \(h(2) = 48\)
- \(h(3) = 51\)
- \(h(4) = 42\)
So the points are:
- \( (0, 6) \)
- \( (1, 33) \)
- \( (2, 48) \)
- \( (3, 51) \)
- \( (4, 42) \)
From the options you provided, the correct set of coordinates is: (0, 6), (1, 33), (2, 48), (3, 51), and (4, 42).