A volleyball is served at an angle of 35 degrees with an initial speed of 5 m/s. What is the maximum height reached by the ball?

Answer 1

Vo = 5m/s[35o]
Yo = 5*sin35 = 2.87 m/s.

Y^2 = Yo^2 + 2g*h = 0
h = -Yo^2/2g = -(2.87)^2/-19.6 = 0.42 m

Answer 2

A volleyball is served at an angle of 35 degrees with an initial speed of 5 m/s. What is the maximum height reached by the ball?

how find the maximum

Answer 3

compute for the range of the volleyball when it was served at an angle 50° to the horizontal with an initial velocity of 35 m/s.