To find the volume of the iodine-131 solution needed, we need to use the relationship between activity, volume, and radioactivity.
Activity = Volume x Radioactivity
Let's call the volume of the solution V. Now we can plug in the given values:
2.6 m Ci = V x 2.0 mCi/mL
Solving for V:
V = 2.6 m Ci / 2.0 mCi/mL
V = 1.3 mL
Therefore, 1.3 mL of the iodine-131 solution is used to prepare the atomic cocktail.
A vial contains radioactive iodine-131 with an activity of 2.0 mCi/mL. If a thyroid test requires 2.6 m Ci in an "atomic cocktail," how many milliliters are used to prepare the iodine-131 solution?
Express the volume to two significant figures and include the appropriate units.
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