altitude of top of flagpole
= 40+72tan17
length of cable:
length^2=altitude^2+72^2
A vertical pole 40 feet tall stands on a hillside that makes an angle of 17 degrees with the horizontal. Approximate the minimum length of cable that will reach the top of the pole from a point on the hillside 72 feet downhill from the base of the flagpole.
3 answers
Hmmm. The 72 feet is measured on the slope, not out from the pole horizontally. I get
top of pole is at
40 + 72 sin17°
downhill point is
72 cos 17°
from point beneath the pole
cable^2 = (40+72 sin17°)^2 + (72 cos 17°)^2
top of pole is at
40 + 72 sin17°
downhill point is
72 cos 17°
from point beneath the pole
cable^2 = (40+72 sin17°)^2 + (72 cos 17°)^2
vertical pole 20 feet high is sighted horizontally from a point 75 feet from its base up the sloping side site of a hill on which it rest.what is the inclination of the slope?
1 answer