a vector has a magnitude of 3.5 m and points in a direction that is 145 degrees below the x axis.find the x and y component of this vector

Answer 1

145 degrees below the x-axis? Really? 90 degrees would be pointing straight down!
That's pointing backwards.
In any case, the components would be
x = 3.5 cos theta
y = 3/5 sin theta
where theta is measured from the x-axis.

Hint: DRAW THE VECTOR!

Answer 2

145o below +x-axis = 360-145 = 215o CCw.

V = 3.5m[215o].
X = 3.5*Cos215 =
Y = 3.5*sin215 =