A varies BC when B=4,C=9,A=6. Find the fomula that connect A, B, C

1 answer

To find a formula that relates \( A \), \( B \), and \( C \), we can assume a form of relationship based on how \( A \) varies with respect to \( B \) and \( C \).

Given that \( A = 6 \) when \( B = 4 \) and \( C = 9 \), we can create an equation based on the proportionality of \( A \) to \( B \) and \( C \). A common assumption is that \( A \) is directly proportional to both \( B \) and a power of \( C \).

Let's explore a formula of the form: \[ A = k \cdot B^m \cdot C^n \] where \( k \), \( m \), and \( n \) are constants to be determined.

Plugging in the given values: \[ 6 = k \cdot 4^m \cdot 9^n \] To solve for \( k \), \( m \), and \( n\), we need additional information about how \( A \) varies with \( B \) and \( C \).

Without that information, we can still suggest a simple form. If we assume \( A \) is directly proportional to \( B \) and inversely proportional to \( C \), a possible form could be: \[ A = k \cdot \frac{B}{C} \] Substituting the known values: \[ 6 = k \cdot \frac{4}{9} \] Multiplying both sides by \( \frac{9}{4} \): \[ k = 6 \cdot \frac{9}{4} = \frac{54}{4} = 13.5 \]

Thus, the relationship becomes: \[ A = 13.5 \cdot \frac{B}{C} \]

So, a possible equation that relates \( A \), \( B \), and \( C \) is: \[ A = 13.5 \cdot \frac{B}{C} \]

However, keep in mind that there are many possible relationships between these variables, and more information would help to define a more precise formula.