A Van de Graaff generator is charged so that the magnitude of the electric field at its surface is 3.0 multiplied by 104 N/C.

(a) What is the magnitude of the electric force on a proton released at the surface of the generator?

(b) Find the proton's acceleration at this instant.

2 answers

Force= Eq, right?
solve, you know the charge of a proton.

F=ma solve for a.
a) Force = E*e
where E is the field in N/C and e is the electron (and proton) charge,
1.6*10^-19 C

b) acceleration = Force/(proton mass)