Diameter = 1000rev/min ÷ 60s * 2π * 2.9cm ÷ (2π * 31rev/s)
Diameter = 1.56cm
A vacuum pump is connected to its electric motor by a belt drive (Fig. 9-40, not to scale). The motor rotates at a rate of 1000 rev/min and the diameter of the motor shaft is 2.9 cm. How large (diameter) should the pulley be if it is designed for a speed of 31 rev/s? (Answer: 1.56cm)
Answer is provided above. Please show all work on how to get the answer as 1.56cm.
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