A university football stadium has 81,500 seats. The stadium is at full capacity on game day. Layla believes only 79,000 seats are occupied. Find the percent error of Layla’s prediction. Round your answer to the nearest hundredth of a percent.(1 point)

Responses

3.07%
3.07%

−3.07%
negative 3.07 percent

90.3067%
90.3067%

0.0307%
0.0307%
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1 answer

To find the percent error of Layla's prediction, we use the formula for percent error:

\[ \text{Percent Error} = \left| \frac{\text{Actual Value} - \text{Predicted Value}}{\text{Actual Value}} \right| \times 100 \]

In this case, the actual value (full capacity of the stadium) is 81,500 seats, and Layla's predicted value is 79,000 seats.

Substituting the values into the formula:

\[ \text{Percent Error} = \left| \frac{81,500 - 79,000}{81,500} \right| \times 100 \]

Calculating the numerator:

\[ 81,500 - 79,000 = 2,500 \]

Now divide by the actual value:

\[ \frac{2,500}{81,500} \approx 0.0307 \]

Now multiply by 100 to convert to a percentage:

\[ 0.0307 \times 100 \approx 3.07% \]

Thus, the percent error of Layla's prediction is approximately 3.07%.

Therefore, the correct response is:

3.07%