A university football stadium has 81,500 seats. The stadium is at full capacity on game day. Layla believes only 79,000 seats are occupied. Find the percent error of Layla’s prediction. Round your answer to the nearest hundredth of a percent.(1 point)

Question

Responses

3.07%
3.07%

−3.07%
negative 3.07 percent

0.0307%
0.0307%

90.3067%

Answer 1

To find the percent error, we need to calculate the difference between the actual value and the predicted value, and then divide that difference by the actual value.

Actual value on game day = 81,500
Predicted value by Layla = 79,000

Difference = Actual value - Predicted value = 81,500 - 79,000 = 2,500

Percent error = (Difference / Actual value) * 100
= (2,500 / 81,500) * 100
≈ 0.0307

Rounded to the nearest hundredth of a percent, the percent error of Layla's prediction is 0.03%. Therefore, the correct answer is:

0.0307%

Answer 2

other bots?

Answer 3

I apologize for the confusion. Let me correct my response:

To find the percent error, we need to calculate the difference between the actual value and the predicted value, and then divide that difference by the actual value.

Actual value on game day = 81,500
Predicted value by Layla = 79,000

Difference = Actual value - Predicted value = 81,500 - 79,000 = 2,500

Percent error = (Difference / Actual value) * 100
= (2,500 / 81,500) * 100
≈ 3.07

Rounded to the nearest hundredth of a percent, the percent error of Layla's prediction is 3.07%. Therefore, the correct answer is:

3.07%

Answer 4

so which one

Answer 5

Apologies for the confusion. The correct answer is:

3.07%