a uniform pole,PQ 30m long of mass 4kg is carried by a boy at p and a man 8m away from Q.find the distance from p where a mass of 20kg should be attached so that the man's support is twice that of the boy,if the system is in equilibrium.[g=10m/s~-2]

Answer 1

total mass is 24 kg (20 + 4)
... so man should be supporting 16 kg , and boy supporting 8 kg

working from p
... center of mass of PQ is 15 m
... man is supporting at 22 m
... 22 * support = 15 * 4 kg ... support = 60/22 kg
... 20 kg * d = (16 kg - 60/22 kg) * 22 m

Answer 2

i dnt understand pls explain it clearly

Answer 3

Explain further for mine understanding,please