sum moments about the piviot;
90(50-40)+72(70-40)+M(10-40)=0
solve for M
A uniform metre rule of mass 90g is pivoted at the 40cm mark. If the rule is in equilibrum with an unknown mass, M placed at the 10cm mark and 72g mass at the 70cm mark, determine M.
Please help me urgently!!
2 answers
Please explain how and why bobpursley