Asked by Richard

A uniform metre rule of mass 90g is pivoted at the 40cm mark. If the rule is in equilibrum with an unknown mass, M placed at the 10cm mark and 72g mass at the 70cm mark, determine M.

Please help me urgently!!
Answered by bobpursley
sum moments about the piviot;
90(50-40)+72(70-40)+M(10-40)=0
solve for M
Answered by Richard
Please explain how and why bobpursley
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