A uniform meter stick with a mass of 210 g is supported horizontally by two vertical strings, one at the 0 cm mark and the other at the 90 cm mark (Fig. 9-57).

Question

A uniform meter stick with a mass of 210 g is supported horizontally by two vertical strings, one at the 0 cm mark and the other at the 90 cm mark (Fig. 9-57).
(a) What is the tension in the string at 0 cm?
 
(b) What is the tension in the string at 90 cm?

bobpursley · Answer

the weight (.210*9.8N) is at the center of gravity at the 50cm mark.

Summing moments about the 0 mark,
.210*9.8*.5-W1*.90=0 Solve for W1, the tension i string at 90 cm
The sum of tensions=weight
W1+W2=.210*9.8
solve for W2

Eliza · Answer

Got it! thank you so much

Babatunde · Answer

I am african Warlord andn I have rpg haha