To calculate the mass of the meter rule, we need to consider the balance of torques around the knife edge.
The torque at point A due to the meter rule is 70 kg * 9.81 m/s^2 * 0.40 m = 274.8 Nm.
The torque at point A due to the mass of the meter rule (m) can be represented as m * 9.81 m/s^2 * L, where L is the distance from the knife edge to the center of mass of the meter rule (assuming it is uniform) and we know L = 0.5 m.
Since the system is in equilibrium, the sum of the torques must be zero. Therefore, we can set up the equation as follows:
274.8 Nm = m * 9.81 m/s^2 * 0.5 m
m = 56.03 kg
Therefore, the mass of the meter rule is 56.03 kg.
A uniform meter rule ab is placed horizontally on a knife edge placed 40 cm from a and with a mass of 70 kg at a what is the mass of the meter rule
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