(E-field)*(Area)*sin37 = ___
newton*m^2/Coulomb
You should have provided units for your E-field, area and angle. I assumed that are N/C, square meters and degrees
A uniform electric field of magnitude 2.10×10^4 makes an angle of 37 with a plane surface of area 1.60×10^−2 .What is the electric flux through the surface?
1 answer