A uniform electric field is directed upward and has a magnitude of 5 N/C. What are the magnitude and direction of the force on a charge of -3 C placed in this field?
F=Eq
E=5
q=-3
5(-3)=-15N Downward
Ok I have the downward correct the -15 is incorrect. Did I use the wrong equation?
2 answers
Your F = E q formula is correct. Are you sure the charge was 3 Coulombs and not 3 microcoulombs (3 uC) ?
I'm sure... I copy/paste this question on here to be sure I got it right.
1 answer