a) dV/dr = E
=> V = E*r
=> V = 10^2 * 10^-2m
= 1V
b) Change in potential energy = U = qV
Charge on a proton = q = 1.6*10^-19
U = (1.6*10^-19)*V
= (1.6*10^-19)*1
= 1.6*10^-19J
A uniform electric field of magnitude 1.0×10^2 NC^−1 exists between two conducting plates, one of which is positively charged and the other of which is negatively charged. The plates are 10 mm apart.
(a) Calculate the magnitude of the potential difference between the plates.
(b) If a proton is moved from the positive plate to the negative plate, what is the magnitude of the change in its electrostatic potential energy?
(c) If this device operates as a capacitor, how is it able to store electrostatic potential energy?
1 answer
1 answer