A uniform door (0.81 m wide and 2.1 m high) weighs 122 N and is hung on two hinges that fasten the long left side of the door to a vertical wall. The hinges are 1.5 m apart. Assume that the lower hinge bears all the weight of the door.

Question

(a) Find the magnitude and direction of the horizontal component of the force applied to the door by the upper hinge.
magnitude N
direction ---Select--- to the left to the right upwards downwards
(b) Find the magnitude and direction of the horizontal component of the force applied to the door by the lower hinge.
magnitude N
direction ---Select--- to the left to the right upwards downwards
(c) Determine the magnitude and direction of the force applied by the door to the upper hinge.
magnitude N
Direction ---Select--- to the left to the right upwards downwards
(d) determine the magnitude and direction (below the horizontal) of the force applied by the door to the lower hinge.
magnitude N
direction

I was able to find the direction but not sure what is mean by the magnitude

Answer 1

Magnitude is the length of the force vector. Take the square root of the sum of the squares of the vertical and horizontal force components. You must knw these components if you got the direction right.

Answer 2

09998/88