torque=force*radius*sinTheta where theta is the angle between position vector and direction of force. T1=315*1.31*sin90 ; T2=315*1.31*sin180; T3=315*1.31*sin135
so for total torque, add them Notice T3 is a subtractive force.
A uniform disk with mass m = 9.42 kg and radius R = 1.31 m lies in the x-y plane and centered at the origin. Three forces act in the +y-direction on the disk: 1) a force 315 N at the edge of the disk on the +x-axis, 2) a force 315 N at the edge of the disk on the –y-axis, and 3) a force 315 N acts at the edge of the disk at an angle θ = 35° above the –x-axis.
3) What is the magnitude of the torque on the disk about the z axis due to F3?
6) What is the z-component of the net torque about the z axis on the disk?
1 answer
1 answer