Let's go through each part of the problem step by step.
Part A: Determine the rate of decay
Given that 6% of the caffeine in the body is metabolized and eliminated every hour, the remaining amount of caffeine after one hour is 100% - 6% = 94%.
Thus, the rate of decay is 6% per hour.
Part B: Initial amount of caffeine
According to the problem, the initial amount of caffeine consumed in this scenario is 100 mg.
Part C: Write \(C(t)\) as a function of \(t\)
We know that the initial amount \(C(0)\) is 100 mg, and after each hour, 94% of the caffeine remains. This results in an exponential decay function: \[ C(t) = C(0) \times (1 - \text{decay rate})^t \] Plugging in the values we have: \[ C(t) = 100 \times (0.94)^t \]
Part D: Fill out the table
Now, we can calculate \(C(t)\) for \(t = 0\), \(t = 1\), \(t = 3\), and \(t = 5\).
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For \(t = 0\): \[ C(0) = 100 \times (0.94)^0 = 100 \times 1 = 100 \text{ mg} \]
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For \(t = 1\): \[ C(1) = 100 \times (0.94)^1 = 100 \times 0.94 = 94.00 \text{ mg} \]
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For \(t = 3\): \[ C(3) = 100 \times (0.94)^3 \approx 100 \times 0.830584 = 83.06 \text{ mg} \]
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For \(t = 5\): \[ C(5) = 100 \times (0.94)^5 \approx 100 \times 0.735091 = 73.51 \text{ mg} \]
Final table
Here are the values for \(C(t)\) rounded to the nearest hundredth:
| t | C(t) | |:-------:|:----------:| | 0 | 100.00 | | 1 | 94.00 | | 3 | 83.06 | | 5 | 73.51 |
In summary, the answers are:
- Part A: 6%
- Part B: 100 mg
- Part C: \(C(t) = 100 \times (0.94)^t\)
- Part D:
- \(C(0) = 100.00\)
- \(C(1) = 94.00\)
- \(C(3) = 83.06\)
- \(C(5) = 73.51\)