A two-stage rocket moves in space at a constant velocity of +4890 m/s. The two stages are then separated by a small explosive charge placed between them. Immediately after the explosion the velocity of the 1380-kg upper stage is +5660 m/s. What is the velocity (magnitude and direction) of the 2970-kg lower stage immediately after the explosion?

1 answer

M1*V + M2*V = M1*V1 + M2*V2.
1380*4890 + 2970*4890 = 1380*5660 + 2970*V2. V2 = ?.