F = q1*q2/d^2
so,
q1(7.50*10^-6 - q1)/.561^2 = 0.100
(a) Two point charges totaling 7.50 µC exert a repulsive force of 0.100 N on one another when separated by 0.561 m. What is the charge on each?
2 answers
Dropped the k there Steve.
F = kq^2/r^2
q= sqrt(Fr^2/k)
F = kq^2/r^2
q= sqrt(Fr^2/k)